Non-Right Triangle - SSA - Ambiguous Case
Author: Jerel L. Welker

Move the sliders to select the appropriate triangle.
The show circle checkbox for side a will make a circle visible with a radius of a demonstrating the two possible sides.
Check the show solutions checkbox to show the solutions.

Jerel L. Welker
Lincoln Southwest High School
Lincoln, NE
jwelker@lps.org

Show SSA Solutions

"b = " + d

Show circle determining side A

m

Show Triangle Height

α = 0.5235987755982988 rad (slider from 0 to 3.141592653589793, step 0.017453292519943295)
a_1 = 10 (slider from 0 to 30, step 0.1)
b_1 = 20 (slider from 0 to 30, step 0.1)
m = true
A = Intersect(xAxis, yAxis)
F = Point(xAxis)
c_1 = Ray(A, F)
F' = Rotate(F, α, A)
β = Angle(F, A, F')
d_1 = Ray(A, F')
e = Circle(A, b_1)
C = Intersect(e, d_1, 1)
b = Segment(A, C)
c = Circle(C, a_1)
D, B = Intersect(c, c_1)
f = Segment(C, B)
g = Segment(C, D)
h = true
i = Segment(A, D)
E = Point(i)
text1: "AD= " + i
j = Segment(A, B)
G = Point(j)
k = OrthogonalLine(C, c_1)
H, I = Intersect(c, k)
a = Segment(H, C)
γ = Angle(C, D, A)
δ = Angle(C, B, A)
text2: "AB = " + j
d = OrthogonalLine(C, c_1)
J = Intersect(d, c_1)
l = Segment(C, J)
text3: "(" + b + ")sin(" + β + ") = " + l + " > " + a
n = true